Neco real Mathematics Obj and theory Now available

By 07:28 Fri, 04 Jul 2014 Comments


Maths - Type A

1-10: DBBADBABEE

11-20: CABBEEBBBC

21-30: BCDEBCBCDB

31-40: AEBCDAEDBD

41-50: ABADCEBAED

51-60: BEBDBEDEDA

Maths - TYPE B

1-10: CABBAEBACC

11-20: AEBCDAEDDB

21-30: DEBDBEDEDC

31-40: BBBABBABED

41-50: ECDEBBDBBC

51-60: ADADCECAED

Maths - TYPE C

1-10: BEBDAEDEDA

11-20: EDAEBBDBAB

21-30: ADADDCABEA

31-40: AABBCAEDDB

41-50: DBDBABBBCC

51-60: BBBAEBABEE

Maths - Type D

1-10: ABADCEBAED

11-20: BBBAEBABEE

21-30: AEBCDAEDDB

31-40: DCDEBCBCDB

41-50: BEBDBEDEDA

51-60: CABBEEBABC

(3a.)

13/4 +X/Y = 4/3

X/Y=4/5-13/16

X/Y=64-65/(16)(5)

X/Y= -1/80

X:Y = -1:80

(3b.)

cost each machines

= 25,000/12

= 2083.3naira.

i. cost of machines

= 2083.3 *10

=20833.30

ii. number of such machines

= 175,000/2083.3

=84 machines

(4)

(i) draw a venn diagram

U = universal set =40

mangoes (M) = 15

Pineapples(P)= 21

(ii)

let X reps the no. that do not like mangoes and pineapples

ii. 9+6+15+X = 40

30+X =40

X = 40-30

X =10

(III)

. % of class of mangoes only

= 9/40 * 100 = 22.5%

(6)

(i)

using pythagoras

OQ^2 = OR^2 + QR^2

15^2 = 6^2 + QP^2

QR^2 = 225 - 36

QR^2 = 189 , QR = SQR OF 189

QR = 13.75cm

lenght of chord = PR + QR

= 13.75 + 13.75

= 27.50cm

(II)

Lenght of chord (PQ)

= 2r sin(tita/2) , r = 15cm

27.50 = 2*15*sin(tita/2)

sin(tita/2) = 27.50/30

sin(tita/2) = 0.9165

tita/2 = sin^-1(0.9165)

tita/2 = 66.42

tita = 66.42 *2

tita = 133degree

(iii)

perimeter = lenght of arc + lenght of chord

lenght of arc = tita/360 *2(pile)r

= 133/360 * 2 *22/7 *15

= 34.83cm.

perimeter (P) = 34.83 + 27.50

= 62.30cm

= 62.3cm.

(8)

tabulate . please note that the way you interprete logarith table is diff

No:

10900,root3 10900, 392.9, (392.8)^3, 39.436, 12.03. (12.03)^3, 39.436*(12.03)^3, (root3(10900)*(392.8)^3)/((39.436*12.03)^3), antilog 1.96*10^4

Log:

4.03744, 4.0374/3= 1.3458, 2.594.2, 2.5942*(3)= 7.7826, 1.3458, 7.7826, 1.5959, 1.08003,1.0803*3=3.2409, 1.5959*3=3.2409, 1.5959+3.2409=4.38368, 9.1284, 4.8368, 9.1284+ 4.8368=4.2916

(5)

a)244basen=1022base4

2*n^2+4*n^1+4*n^0=1*4^3+0+4^2+2*4^1+2*4^0

2n^2+4n+4=64+0+8+2

2n^2+4n+4=74

2n^2+4n+4-74=0

2n^2+4n-70=0

n^2+2n-35=0

n^2-5n+7n-35=0

n(n-5)+7(n-5)=0

n+7=0 or n-5=0

n=-7 or n=5

b)Using similar triangle

AZ/XZ=KZ/YZ

8/XZ=11/24

XZ=(8*24)/11

=17.45cm

(1)

(a)

peugeout sector= 180/480*(360)

=135 degree

datsun sector= 108/480*(360)

ford sector= 72/480*360

=54 degree

toyota sector= 56/480*(360)

=48 degree

(b)

Pr(toyota)= 42/480

Pr(volkswagen)= 48/480

Pr(toyota or volkswagen)= (42/480)+ 48/480

=90/480= 9/48

=3/16

(2)

(a) given (a^2-4b^2)

=(a^2-4b^2)/(a^2-3ab-2ab+6b^2)=(a^2-4b^2)/(a(a-3b)-2b(a-3b)

=a^2-(2b)^2/(a-2b)(a-3b))= (a-2b)(a+2b)/(a-2b)(a-3b)

=a+2b/(a-3b)

(2b)

forth term(f4)=-3

ninth term(f9)=123

fn=a+(n-1)d

f4=a+3d

f9=a+8d

a+3d=-3, eqn (1)

a+8d=12, eq(2)

subtract eq(1) from eq(2)

a-a+8d-3d=12-(-3)

5d=15

d=15/5=3

using eq(1)

a+3d=-3

a+3(3)=-3

a+9=-3, a=-3-9

(i) common difference(d)=3

(ii)sum of the first seven terms

sn=n/2(2a+(n-1)d)

s7=7/2

(9)

Total surface area(A)=88cm^2

Height (H)=7cm

i)A=2*pie*r*h+2*pie*r^2

A=2*pie*r(h+r)

88=2*22/7*r(7+r)

88=6.29*r(7+r)

7r+r^2=88/6.29

7r+r^2=14

r^2+7r-14=0

using almighty formular

r=-7+_root(7^2-4*1*-14)/2

r=-7+_root(49+56)/2

=-7+_root(105)/2

=-7+_10.25/2

r=-7-10.2/2 or-7+10.25/2

r=-8.625 or 1.625

Diameter(d)=2r

2*1.625

=3.625

ii)Volume of the solid(v)

=pie*r^2*h

=22/7*(1.625)^2*7

=406.66/7

=58.09cm^3

b) =74degrees

(11)

Sack A

Blue(b)=10

Red(r)=6

total=16

Sack B

Blue(b)=9

Red(r)=12

total=21

pr(drawing b from sack A)=10/16

pr(drawing the second ball b from sack A)=9/15

pr(r from sack A)=6/16

pr(r from sack A)=5/15

pr(b from sack B)9/21

pr(second b from sack B)=8/20

pr(all the four crayons are blue)

=(10/16*9/15)*(9/21*8/20)

=9/240*72/420

=9/24*18/105

=3/8*18/105

=27/420

=9/140

More LOADING.


DOWNLOAD NOW

DOWNLOAD MUSIC





Related Article

Comment
Name




.....................

Please LOGIN or REGISTER To Gain Full Access To This Article