# Maths 2016 GCE Subscribers Portal

By 05:05 Fri, 09 Sep 2016 Comments

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Saturday, 10th September, 2016

General Mathematics (Essay&Obje

9.30am-3.30pm

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VERIFIED MATHEMATICS OBJECTIVE

11~20 DCCCCACDBA

21~30 BDBAABDACA

31~40 CCACBDCDBD

41~50 DACBDABBBC

Dear Candidate

Here Are The Symbol To Be Use For Physic And Mathematics Exam

PHYSICS AND MATHEMATICS SYMBOLS TO BE USED FOR EXAM

/ means DIVISION

* means Multiplication

tita You Should Know that.

rais means Raise to power

Or

^ means Raise to power

sqr rut/square rut means Square root

----(1) means Equation 1

yr means Year

f(x-xbar) means x MINUS x BAR as in statistics which means that MINUS will be on Top of x.

, (Comma) means NEXT LINE, This means that The Following Number is Under The Number its Following ie. UNDER. It is usually used during STATISTICS when drawing a table.

EXAMPLE 1.

X: 1,2,3,4,5,6

FX: 4,6,8,10,12

FX-Xbar: 10,8,6,4,2,1

DRAW A TABLE WITH

X|FX|(FX-Xbar)

The above statement means that:

~For X, it has 1 2 3 4 5 6 under it. which means 1 is under 2, 2 is under 1, 3 is under 2, 4 is under 3 and so on...

~Under FX you have 4, then 6 under 4, then 8 under 6, then 10 under 8, then 12 under 10.....

~Under FX-Xbar you have 10, then 8 under 10, then 6 under 8, then 4 under 6, then 2 under 4, then 1 under 2....

ANOTHER EXAMPLE:

Class interval: 60-64,65-69,70-74,75-79,80-84,85-89,90-94,95-99.

X: 62,67,72,77,82,87,92,97.

F: 2,3,6,11,8,7,2,1.

FX: 124,201,432,847,656,609,184,97.

F(x-x bar)2: 561.12,414.18,273.36,33.66,84.48,476.42,351.12,333.06

MEANING OF THE ABOVE EXPRESSION

Bar means Minus on top of d number or Variable and comma means next line which means each of them are unda. Eg 60-64 is unda Class interval, then 65-69 is unda 60-64,etc .So comma means unda.

NOTE : When You See Something Like the above to Examples, You are requered to Draw a Table.

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WARNING : Please Study the above Symbols, If you Dnt want to write Rubbish in you MATHEMATICS Exam Or Calculation Exam

Use this

1a )

6whole 1 / 2 - 3 whole 2/ 5 / 2whole 1 / 2 - 1 whole 3/ 5

25 / 4- 17 / 5 , / 5/ 2- 8/ 5

125 - 68 / , 20 , / 25 - 16,

/ 10

==> 57 / 20 / 9/ 10

=57 / 20 /9 / 10

=57 / 20 x 10 / 9

=57 / 20 x 10 / 9

=57 / 18

= 3whole 1 / 6

=======

3a)

c= -1, y= -3, z= -4 and w= -7

x^2 - y^2 / 2w - z

(-1)^3 - (-3)^2 / 2(-7) -(-4)

= -1-9/+4+4 = -10/-10

= 1

3b)

Considering

y + n + MQN = 180 degree

y + 44 + 44 = 180

y = 180 - 88

Y =92 degree

4a)

2/3(1-4x) -1/2(5-3x) less/equal to 1/4(7+9x)-1/3

multiply through by 12

8(1-4x) -6(5-3x) less/equal to 3(7+9x)-4

8-32x-30+18x less/equal to 21+27x-4

-32x+18x - 27x less/equal to 21-4+30-8

-41x less/equal to 39

x less/equal to -39/41

4b)

DRAW THE ANGLE

from DTMR/

Tan65degree = TR/3

TR = 3Tan65

= 3 x 22.1445

From DRMB

Tan20 = RB/3

RB = 3Tan20

= 3 x 0.3640

= 1.092m

H = TR+RB

= 6.4335 + 1.092

= 7.5255

= 7.53m

5)

Area of shed segment = Area of Sector - Area of Triangle

=Φ/360*πr^2 - (½abSinc)

=\$90/360*22/7*7^2) - ½*7*7*sin90`

=154/4 - 42/2

=(754-98)/4

=56/4

=14cm^2

Cost of painting it =14*750

=N10500

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6a)

Taxable income = x

25/100 x x/1

= 14,000

25x=1400000

X=1400000/25

X= 560000

Total income =

56,000/4 x 5

=70,000

6b)

Education = 2/5

Clothes = 1/6

Food = 3/8

Expenditure = 2/5 + 1/6 + 3/8

48+20+45/120

= 113/120 * 36,000/1

Le 39,000

Savings annually = Le 21,000

To save Le 63,000.00

To save Le 63,000/2100 yrs

= 30 years

(7a )

diagram

(7b )

Angula difference in long (tita)=42 - 12

tita=30 degree

(7bi )

lenght of chord Xy=2 Rsin tita /2

XY= 2*6400*Sin 30 /2

=2 *6400*sin 15 degree

=12800 *0. 2588

=3 . 312 . 64 km

=3312. 64 km

=3310km (to the nearest 10 km )

(7bii )

let the angle that the chord xy substends at the centre of the earth be alpha degree

diagram

sin alpha/ 2= opp / hyp =/ NY/ / 6400

/NY/ = 1/ 2 /XY /= 1/ 2 * 3312. 64

=1656. 32 km

sin alpha/ 2= 1656. 32 / 6400

sin alpha/ 2= 0 . 25888

alpha/ 2= sin ^ - 1(0. 2588)

alpha/ 2=14 . 999

alpha=14 . 999 *2

alpha= 29 . 998

alpha= 30 . 0 degree (to 1 dp )

(7biii)

XY bar= tita/ 360 * 2 pie R cos lat

=30 degeree / 360 * 2*3 . 142 * 6400* cos 60

XY bar= 30 / 360 * 2* 3. 142 * 6400* 0. 5

XY bar= 1675. 73 km

8a)

Drawing

8bi)

Using Pythagoras theory

|xz|² =550²+320²

= 302500+102400=404900

xz=√404999

=636km(3 s.f)

Total distance = 320+550+636

= 1506km

8bii)

Using SOHCAHTOA

Tan z = 320/550

Z= Tan-¹ (320/550)

Z= Tan-¹(0.5818)

Z = 30°

From the diagram in 8a

Bearing of X from Z = 55+30

= 085° or N85°E

9b)

Distance= speed * time

Distance= 3km/h * 3mins

= 3000m/60min * 3min

=50*3 =150min.

9bi)

Circumference= 150m

2π(r+1) = 150

22/1 * 22/7 * (r+1)= 150

r+1= 150*7/44

=1050/44

r+1 = 23.9 ≈ 24 to the nearest whole number.

r+1= 24

r=24-1 = 23min

9bii)

Volume of cylinder=πr²h

Volume= 22/7 * (23)² * 8

22/7 * 529/1 * 8/1

= 93104/7 = 13,300.57

13301m³ to the nearest whole number

10 a )

GIVEN : y = 2X ^2 - 3X – 1

When x = -3

Y = 2(- 3)^2 - 3(- 3) – 1 = 18 + 9 – 1 = 26

When x= - 1

Y = 2(- 1)^ 2 – 3 (-1 )-1 = 2+ 3- 1 = 4

When x = 1

Y = 2(- 1)^ 2 – 3 (1)- 1 = 2 – 3 – 1 = -2

When x = 2

Y =2 (2)^2 -3 (2)- 1= 8 – 6 – 1 = 1

When x = 3

Y = 2(3)3 -3 (3)- 1 = 18 - 9- 1 = 8

When x = 4

Y = 2(4 )^3 – 3(4 )-1 = 32 -12 - 1 = 19

TYPING IN PROGRESS

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IN Progressssss

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VERIFIED MATHEMATICS OBJECTIVE

11~20 DCCCCACDBA

21~30 BDBAABDACA

31~40 CCACBDCDBD

41~50 DACBDABBBC

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