Maths 2016 GCE Subscribers Portal

By 05:05 Fri, 09 Sep 2016 Comments


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Saturday, 10th September, 2016

General Mathematics (Essay&Obje

9.30am-3.30pm

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VERIFIED MATHEMATICS OBJECTIVE

1~10 ABCDBCBADB

11~20 DCCCCACDBA

21~30 BDBAABDACA

31~40 CCACBDCDBD

41~50 DACBDABBBC












Dear Candidate

Here Are The Symbol To Be Use For Physic And Mathematics Exam

PHYSICS AND MATHEMATICS SYMBOLS TO BE USED FOR EXAM

/ means DIVISION

* means Multiplication

tita You Should Know that.

rais means Raise to power

Or

^ means Raise to power

sqr rut/square rut means Square root

----(1) means Equation 1

yr means Year

f(x-xbar) means x MINUS x BAR as in statistics which means that MINUS will be on Top of x.

, (Comma) means NEXT LINE, This means that The Following Number is Under The Number its Following ie. UNDER. It is usually used during STATISTICS when drawing a table.

EXAMPLE 1.

X: 1,2,3,4,5,6

FX: 4,6,8,10,12

FX-Xbar: 10,8,6,4,2,1

DRAW A TABLE WITH

X|FX|(FX-Xbar)

The above statement means that:

~For X, it has 1 2 3 4 5 6 under it. which means 1 is under 2, 2 is under 1, 3 is under 2, 4 is under 3 and so on...

~Under FX you have 4, then 6 under 4, then 8 under 6, then 10 under 8, then 12 under 10.....

~Under FX-Xbar you have 10, then 8 under 10, then 6 under 8, then 4 under 6, then 2 under 4, then 1 under 2....

ANOTHER EXAMPLE:

Class interval: 60-64,65-69,70-74,75-79,80-84,85-89,90-94,95-99.

X: 62,67,72,77,82,87,92,97.

F: 2,3,6,11,8,7,2,1.

FX: 124,201,432,847,656,609,184,97.

F(x-x bar)2: 561.12,414.18,273.36,33.66,84.48,476.42,351.12,333.06

MEANING OF THE ABOVE EXPRESSION

Bar means Minus on top of d number or Variable and comma means next line which means each of them are unda. Eg 60-64 is unda Class interval, then 65-69 is unda 60-64,etc .So comma means unda.

NOTE : When You See Something Like the above to Examples, You are requered to Draw a Table.

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WARNING : Please Study the above Symbols, If you Dnt want to write Rubbish in you MATHEMATICS Exam Or Calculation Exam

NOTE THAT ANSWERS ARE ARRANGED ACCORDINGLY, SO ALWAYS SCROLL DOWN TO SEE NEW/MORE ADDED ANSWERS

MATHEMATICS ANSWERS INFINITYGURU]

Use this

1a )

6whole 1 / 2 - 3 whole 2/ 5 / 2whole 1 / 2 - 1 whole 3/ 5

25 / 4- 17 / 5 , / 5/ 2- 8/ 5

125 - 68 / , 20 , / 25 - 16,

/ 10

==> 57 / 20 / 9/ 10

=57 / 20 /9 / 10

=57 / 20 x 10 / 9

=57 / 20 x 10 / 9

=57 / 18

= 3whole 1 / 6

=======

3a)

c= -1, y= -3, z= -4 and w= -7

x^2 - y^2 / 2w - z

(-1)^3 - (-3)^2 / 2(-7) -(-4)

= -1-9/+4+4 = -10/-10

= 1

3b)

Considering

y + n + MQN = 180 degree

y + 44 + 44 = 180

y = 180 - 88

Y =92 degree

4a)

2/3(1-4x) -1/2(5-3x) less/equal to 1/4(7+9x)-1/3

multiply through by 12

8(1-4x) -6(5-3x) less/equal to 3(7+9x)-4

8-32x-30+18x less/equal to 21+27x-4

-32x+18x - 27x less/equal to 21-4+30-8

-41x less/equal to 39

x less/equal to -39/41

4b)

DRAW THE ANGLE

from DTMR/

Tan65degree = TR/3

TR = 3Tan65

= 3 x 22.1445

From DRMB

Tan20 = RB/3

RB = 3Tan20

= 3 x 0.3640

= 1.092m

H = TR+RB

= 6.4335 + 1.092

= 7.5255

= 7.53m

5)

Area of shed segment = Area of Sector - Area of Triangle

=Φ/360*πr^2 - (½abSinc)

=$90/360*22/7*7^2) - ½*7*7*sin90`

=154/4 - 42/2

=(754-98)/4

=56/4

=14cm^2

Cost of painting it =14*750

=N10500

========

6a)

Taxable income = x

25/100 x x/1

= 14,000

25x=1400000

X=1400000/25

X= 560000

Total income =

56,000/4 x 5

=70,000

6b)

Education = 2/5

Clothes = 1/6

Food = 3/8

Expenditure = 2/5 + 1/6 + 3/8

48+20+45/120

= 113/120 * 36,000/1

Le 39,000

Savings annually = Le 21,000

To save Le 63,000.00

To save Le 63,000/2100 yrs

= 30 years

(7a )

diagram

(7b )

Angula difference in long (tita)=42 - 12

tita=30 degree

(7bi )

lenght of chord Xy=2 Rsin tita /2

XY= 2*6400*Sin 30 /2

=2 *6400*sin 15 degree

=12800 *0. 2588

=3 . 312 . 64 km

=3312. 64 km

=3310km (to the nearest 10 km )

(7bii )

let the angle that the chord xy substends at the centre of the earth be alpha degree

diagram

sin alpha/ 2= opp / hyp =/ NY/ / 6400

/NY/ = 1/ 2 /XY /= 1/ 2 * 3312. 64

=1656. 32 km

sin alpha/ 2= 1656. 32 / 6400

sin alpha/ 2= 0 . 25888

alpha/ 2= sin ^ - 1(0. 2588)

alpha/ 2=14 . 999

alpha=14 . 999 *2

alpha= 29 . 998

alpha= 30 . 0 degree (to 1 dp )

(7biii)

XY bar= tita/ 360 * 2 pie R cos lat

=30 degeree / 360 * 2*3 . 142 * 6400* cos 60

XY bar= 30 / 360 * 2* 3. 142 * 6400* 0. 5

XY bar= 1675. 73 km

8a)

Drawing

8bi)

Using Pythagoras theory

|xz|² =550²+320²

= 302500+102400=404900

xz=√404999

=636km(3 s.f)

Total distance = 320+550+636

= 1506km

8bii)

Using SOHCAHTOA

Tan z = 320/550

Z= Tan-¹ (320/550)

Z= Tan-¹(0.5818)

Z = 30°

From the diagram in 8a

Bearing of X from Z = 55+30

= 085° or N85°E

9b)

Distance= speed * time

Distance= 3km/h * 3mins

= 3000m/60min * 3min

=50*3 =150min.

9bi)

Circumference= 150m

2π(r+1) = 150

22/1 * 22/7 * (r+1)= 150

r+1= 150*7/44

=1050/44

r+1 = 23.9 ≈ 24 to the nearest whole number.

r+1= 24

r=24-1 = 23min

9bii)

Volume of cylinder=πr²h

Volume= 22/7 * (23)² * 8

22/7 * 529/1 * 8/1

= 93104/7 = 13,300.57

13301m³ to the nearest whole number

10 a )

GIVEN : y = 2X ^2 - 3X – 1

When x = -3

Y = 2(- 3)^2 - 3(- 3) – 1 = 18 + 9 – 1 = 26

When x= - 1

Y = 2(- 1)^ 2 – 3 (-1 )-1 = 2+ 3- 1 = 4

When x = 1

Y = 2(- 1)^ 2 – 3 (1)- 1 = 2 – 3 – 1 = -2

When x = 2

Y =2 (2)^2 -3 (2)- 1= 8 – 6 – 1 = 1

When x = 3

Y = 2(3)3 -3 (3)- 1 = 18 - 9- 1 = 8

When x = 4

Y = 2(4 )^3 – 3(4 )-1 = 32 -12 - 1 = 19

TYPING IN PROGRESS

PLEASE BE PATIENT

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VERIFIED MATHEMATICS OBJECTIVE

1~10 ABCDBCBADB

11~20 DCCCCACDBA

21~30 BDBAABDACA

31~40 CCACBDCDBD

41~50 DACBDABBBC

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